(2x-2)^2+12(2x-2)+36=0

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Solution for (2x-2)^2+12(2x-2)+36=0 equation: 



(2x-2)^2+12(2x-2)+36=0

We multiply parentheses

(2x-2)^2+24x-24+36=0

We add all the numbers together, and all the variables

24x+(2x-2)^2+12=0

We move all terms containing x to the left, all other terms to the right

24x+(2x-2)^2=-12

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